3x3 Magic Square Solution¶
Solution: Here’s a completed 3x3 magic square where each row, column, and diagonal adds up to 15:
| 2 | 7 | 6 |
| 9 | 5 | 1 |
| 4 | 3 | 8 |
- Rows:
- \( 2 + 7 + 6 = 15 \)
- \( 9 + 5 + 1 = 15 \)
-
\( 4 + 3 + 8 = 15 \)
-
Columns:
- \( 2 + 9 + 4 = 15 \)
- \( 7 + 5 + 3 = 15 \)
-
\( 6 + 1 + 8 = 15 \)
-
Diagonals:
- \( 2 + 5 + 8 = 15 \)
- \( 6 + 5 + 4 = 15 \)
Verification:
-
Rows:
\( 2 + 7 + 6 = 15 \)
\( 9 + 5 + 1 = 15 \)
\( 4 + 3 + 8 = 15 \) -
Columns:
\( 2 + 9 + 4 = 15 \)
\( 7 + 5 + 3 = 15 \)
\( 6 + 1 + 8 = 15 \) -
Diagonals:
\( 2 + 5 + 8 = 15 \)
\( 6 + 5 + 4 = 15 \)
This arrangement satisfies all the conditions of a magic square!